AIIMS 2018 Physics Equations of Motion MCQ Question

The calculation shows that at $t = 2$ seconds, the velocity $v$ becomes zero, indicating that the object has come to a stop. The acceleration at this moment is $a = -12 \, \text{m/s}^2$, which signifies that the object is experiencing retardation (deceleration) as it slows down. Since the problem explicitly states that the retardation is $12 \, \text{m/s}^2$, option D correctly reflects this value. Other options are not applicable as they do not provide relevant information or values related to the problem.