AIIMS 2018 Physics Equations of Motion MCQ Question

In uniformly accelerated motion, the distance covered in each interval increases due to the constant acceleration. For the first 10 seconds, the distance $s_1$ can be calculated using the formula $s_1 = \frac{1}{2} a t^2$, where $t = 10$ seconds. In the next 10 seconds, the particle travels an additional distance $s_2 = \frac{1}{2} a (20^2) - \frac{1}{2} a (10^2) = \frac{1}{2} a (400 - 100) = \frac{1}{2} a \cdot 300 = 3s_1$, thus $s_2 = 3s_1$. Options A and B are incorrect because they do not account for the increasing distance due to acceleration, and option D overestimates the distance by assuming a quadratic increase without proper calculation.