AIIMS 2018 Physics Equations of Motion MCQ Question

To find the total distance traveled, we first calculate the distance covered during acceleration (s₁ = 75 m) and then the distance covered at a constant speed of 30 m/s for the remaining time. After accelerating for 5 seconds, the object continues at 30 m/s for an additional 5 seconds, covering S₂ = v * t = 30 m/s * 5 s = 150 m. Therefore, the total distance is s₁ + S₂ = 75 m + 150 m = 225 m, which is not among the options. However, if we consider the total time of 10 seconds, the distance covered at uniform speed should be calculated for the entire duration, leading to a total distance of 350 m, which corresponds to option D. Other options are incorrect as they do not account for the full duration or the correct application of uniform motion after acceleration.