AIIMS2019Physics-Projectile Motion

AIIMS 2019 Physics Kinematics MCQ Question

Type: MCQ-numerical-Medium-Class 11

The formula for the maximum height during projectile motion is, h = (u sinθ)² / 2g Now, Δh/h = 2Δu/u Δh/h = 2 × 2 = 4%

Correct Answer

Option C

Detailed Explanation

The calculation shows that the relative change in maximum height (Δh/h) is proportional to the square of the relative change in initial velocity (Δu/u), specifically Δh/h = 2(Δu/u). Given that Δu/u is 2%, substituting this into the equation yields Δh/h = 2 × 2% = 4%. This demonstrates how small changes in initial velocity can significantly affect the maximum height achieved in projectile motion. Other options are not applicable as they do not provide relevant information or calculations related to the problem.

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