AIIMS2019Physics-Circular Motion

AIIMS 2019 Physics Centripetal Acceleration MCQ Question

Type: MCQ-numerical-Easy-Class 11

An electron is moving in a circle of radius 2 m with speed 4 m/s. Find the acceleration of the electron.

A

8 m/s²

B

4 m/s²

C

16 m/s²

D

10 m/s²

Correct Answer

Option A

Detailed Explanation

The acceleration of an electron moving in a circular path can be calculated using the formula for centripetal acceleration, a=v2ra = \frac{v^2}{r}, where vv is the speed and rr is the radius. Substituting the given values, a=(4m/s)22m=16m2/s22m=8m/s2a = \frac{(4 \, \text{m/s})^2}{2 \, \text{m}} = \frac{16 \, \text{m}^2/\text{s}^2}{2 \, \text{m}} = 8 \, \text{m/s}^2, confirming option (A) as correct. Options (B), (C), and (D) are incorrect as they do not match the calculated centripetal acceleration based on the provided speed and radius.

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