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AIIMS2018Physics-Properties of Solids and Liquids

AIIMS 2018 Physics Surface Tension MCQ Question

Type: MCQ-numerical-Medium-Class 11

A film of water is formed between two straight parallel wires of length 10 cm10\text{ cm} each separated by 0.5 cm0.5\text{ cm}. If their separation is increased by 1 mm1\text{ mm} while still maintaining their parallelism, how much work will have to be done? (Surface tension of water = 7.2×10−2 N/m7.2 \times 10^{-2}\text{ N/m})

A

7.22×10−6 joule7.22 \times 10^{-6}\text{ joule}

B

1.44×10−5 joule1.44 \times 10^{-5}\text{ joule}

C

2.88×10−5 joule2.88 \times 10^{-5}\text{ joule}

D

5.76×10−5 joule5.76 \times 10^{-5}\text{ joule}

Correct Answer

Option B

Detailed Explanation

Option B is correct because it accurately reflects the calculated work done on the soap film, which is derived from the surface tension (T) and the change in area (ΔA). The formula W = T × ΔA shows that the work is directly proportional to both the surface tension and the increment in area, leading to the result of 1.44 × 10⁻⁵ J. Other options are not relevant as they do not provide any alternative calculations or values that pertain to the problem, thus lacking the necessary context to be considered correct. Understanding the relationship between surface tension, area, and work is crucial in applications involving fluid mechanics and surface phenomena.

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