AIIMS2019Physics-Mechanical Properties of Solids
AIIMS 2019 Physics Shear Strain MCQ Question
Type: MCQ-numerical-Medium-Class 11
A 2 m long rod of radius 1 cm which is fixed from one end is given a twist of 0.8 radians. The shear strain developed will be
A
0.002
B
0.004
C
0.008
D
0.016
Correct Answer
Option B
Detailed Explanation
The shear strain (γ) developed in a twisted rod can be calculated using the formula γ = θ / L, where θ is the angle of twist in radians and L is the length of the rod. For a 2 m long rod twisted by 0.8 radians, γ = 0.8 rad / 2 m = 0.4 rad/m. Since the radius is 1 cm (0.01 m), the shear strain is γ = 0.4 rad/m × 0.01 m = 0.004, which corresponds to option B.
Options A (0.002), C (0.008), and D (0.016) are incorrect as they do not accurately reflect the relationship between the angle of twist, length, and radius in calculating shear strain.
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