AIIMS2019Physics-Surface Tension

AIIMS 2019 Physics Work Done in Expanding Bubbles MCQ Question

Type: MCQ-numerical-Medium-Class 11

Find out the work done to expand the soap bubble to radius R = 5 cm (Surface tension of water = 0.1 N/m)

A

2.8 × 10⁻³ J

B

6.28 × 10⁻³ J

C

3.7 × 10⁻³ J

D

5.8 × 10⁻³ J

Correct Answer

Option B

Detailed Explanation

The work done to expand a soap bubble can be calculated using the formula W=4πR2γW = 4\pi R^2 \gamma, where γ\gamma is the surface tension and RR is the radius of the bubble. For a radius R=5cm=0.05mR = 5 \, \text{cm} = 0.05 \, \text{m} and surface tension γ=0.1N/m\gamma = 0.1 \, \text{N/m}, the work done is W=4π(0.05)2(0.1)=6.28×103JW = 4\pi (0.05)^2 (0.1) = 6.28 \times 10^{-3} \, \text{J}, which corresponds to option B. Other options are incorrect as they do not match this calculated value, indicating either miscalculations or incorrect assumptions about the parameters involved.

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