AIIMS2018Physics-Mechanics

AIIMS 2018 Physics Conservation of Momentum MCQ Question

Type: MCQ-conceptual-Medium-Class 11

An explosion breaks a rock into three parts in a horizontal plane. Two of them go off at right angles to each other. The first part of the mass 1 kg1\text{ kg} moves with a speed of 12 m/s12\text{ m/s} and the second part of mass 2 kg2\text{ kg} moves with speed of 8 m/s8\text{ m/s}. If the third part flies off with speed 4 m/s4\text{ m/s}, then its mass is

A

5 kg

B

7 kg

C

17 kg

D

3 kg

Correct Answer

Option A

Detailed Explanation

To solve for the mass of the third part, we apply the principle of conservation of momentum. The momentum in the x-direction from the first part (1 kg at 12 m/s) is 12 kg·m/s, and the momentum in the y-direction from the second part (2 kg at 8 m/s) is 16 kg·m/s. The third part, moving at 4 m/s, must balance the total momentum in both directions, leading to the equation m34=122+162m_3 \cdot 4 = \sqrt{12^2 + 16^2}, which simplifies to m3=5m_3 = 5 kg. Options B (7 kg), C (17 kg), and D (3 kg) do not satisfy the momentum conservation equations, confirming that only option A is valid.

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