AIIMS 2018 Physics Magnetic Field MCQ Question

To find the magnetic field $B$, we substitute the given values into the expression $B = \frac{\mu_0 I}{2\pi d} \sin \phi$. With $\mu_0 = 4\pi \times 10^{-7} \, \text{T m/A}$, $d = 0.01 \, \text{m}$, and $\sin \phi = \frac{1.5}{\sqrt{3.25}} \approx 0.826$, we calculate $B$ to be approximately $1.67 \times 10^{-5} \, \text{T}$. Other options are marked as N/A, indicating they do not provide valid answers or calculations relevant to the question. This exercise reinforces the application of the Biot-Savart law in determining the magnetic field generated by a current-carrying conductor.