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AIIMS2017Physics-Laws of Motion

AIIMS 2017 Physics Tension in Strings MCQ Question

Type: MCQ-numerical-Medium-Class 11

Four blocks of same mass connected by a string are pulled by a force F on a smooth horizontal surface as shown in the figure. The tension T₁, T₂, T₃ will be,

Question diagram
A

T1=14F,  T2=32F,  T3=14FT_1=\frac{1}{4}F,\; T_2=\frac{3}{2}F,\; T_3=\frac{1}{4}F

B

T1=14F,  T2=12F,  T3=12FT_1=\frac{1}{4}F,\; T_2=\frac{1}{2}F,\; T_3=\frac{1}{2}F

C

T1=34F,  T2=12F,  T3=14FT_1=\frac{3}{4}F,\; T_2=\frac{1}{2}F,\; T_3=\frac{1}{4}F

D

T1=34F,  T2=12F,  T3=12FT_1=\frac{3}{4}F,\; T_2=\frac{1}{2}F,\; T_3=\frac{1}{2}F

Correct Answer

Option B

Detailed Explanation

In a system of four blocks connected by strings and pulled by a force FF, the tension in the strings can be determined by analyzing the forces acting on each block. For option B, T1=14FT_1 = \frac{1}{4}F, T2=12FT_2 = \frac{1}{2}F, and T3=12FT_3 = \frac{1}{2}F accurately reflects the distribution of force along the string, considering that the acceleration aa of the entire system is a=F4ma = \frac{F}{4m} (where mm is the mass of each block). The other options incorrectly calculate the tensions by either misapplying Newton's second law or failing to account for the cumulative effect of the blocks on the tension in the strings.

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