AIIMS2000Physics-Ideal Gas Law

AIIMS 2000 Physics Pressure-Temperature Relationship MCQ Question

Type: MCQ-numerical-Medium-Class 11

A flask containing air at 27°C is corked up at atmospheric pressure. The cork can be forced out by a pressure of 2.5 atmosphere. To what temperature the flask should be heated to do that?

A

150 K

B

300 K

C

600 K

D

750 K

Correct Answer

Option D

Detailed Explanation

To solve this problem, we can use the ideal gas law, which states that PV=nRTPV = nRT. In this scenario, we can consider the initial and final states of the gas in the flask. Initially, the pressure is P1=1P_1 = 1 atmosphere (atmospheric pressure) and the temperature is T1=27C=300KT_1 = 27^{\circ}C = 300 K. When the pressure increases to P2=2.5P_2 = 2.5 atmospheres, we need to find the new temperature T2T_2. Using the ideal gas law and the fact that the number of moles (n) and the gas constant (R) remain constant, we can set up the equation: P1T1=P2T2\frac{P_1}{T_1} = \frac{P_2}{T_2} Rearranging gives us: T2=T1P2P1T_2 = T_1 \cdot \frac{P_2}{P_1} Substituting the known values: T2=300K2.51=300K2.5=750KT_2 = 300 K \cdot \frac{2.5}{1} = 300 K \cdot 2.5 = 750 K Therefore, the correct answer is D) 750 K. The other options are incorrect because they do not satisfy the derived equation based on the given pressures and initial temperature.

Found an issue with this question?

Related Questions