AIIMS2018Physics-Gravitational Potential Energy

AIIMS 2018 Physics Vector Calculations MCQ Question

Type: MCQ-numerical-Hard-Class 11

The gravitational field in a region is given by g=5 N/kgi^+12 N/kgj^\vec{g} = 5\text{ N/kg}\hat{i} + 12\text{ N/kg}\hat{j}. The change in the gravitational potential energy of a particle of mass 1 kg1\text{ kg} when it is taken from the origin to a point (7 m,3 m)(7\text{ m}, -3\text{ m}) is:

A

71 J71\text{ J}

B

1358 J13\sqrt{58}\text{ J}

C

71 J-71\text{ J}

D

1 J1\text{ J}

Correct Answer

Option D

Detailed Explanation

The calculation of gravitational potential energy change involves integrating the force per unit mass (I) over the displacement, resulting in v=[Ixx+Iyy]v = -[I_x x + I_y y]. Substituting the given values yields v=[5(7)+12(3)]=1J/kgv = -[5(7) + 12(-3)] = 1 \, \text{J/kg}, which indicates an increase in potential energy, confirming that option D is correct. The other options are not applicable or do not provide relevant information, as they do not pertain to the calculation or interpretation of gravitational potential energy changes. Understanding this concept is crucial for analyzing forces and energy in physics.

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