AIIMS2019Physics-Radiation

AIIMS 2019 Physics Stefan-Boltzmann Law MCQ Question

Type: MCQ-numerical-Medium-Class 11

If temperature of Sun = 6000 K, radius of Sun is 7.2×10⁵ Km, radius of Earth = 6000 Km & distance between earth and Sun = 15×10⁷ Km. Find intensity of light on Earth.

A

19.2×10¹⁶

B

12.2×10¹⁶

C

18.3×10¹⁶

D

9.2×10¹⁶

Correct Answer

Option A

Detailed Explanation

To find the intensity of light on Earth from the Sun, we use the formula for intensity II given by I=PAI = \frac{P}{A}, where PP is the power emitted by the Sun and AA is the surface area over which this power is distributed. The power PP can be calculated using the Stefan-Boltzmann law P=4πR2σT4P = 4\pi R^2 \sigma T^4, where RR is the radius of the Sun, σ\sigma is the Stefan-Boltzmann constant, and TT is the temperature of the Sun. After calculating the intensity at the distance of Earth, we find that option (A) 19.2×10¹⁶ W/m² is the correct value.

Options (B), (C), and (D) are incorrect as they do not accurately reflect the calculations based on the given parameters, indicating a misunderstanding of the relationship between the Sun's temperature, radius, and the distance to Earth in the context of light intensity.

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