MarksRiser
MarksRiser
AIIMS2019Physics-Gravitation

AIIMS 2019 Physics Gravitational Potential Energy MCQ Question

Type: MCQ-numerical-Medium-Class 11

A particle of mass 10 g is kept on the surface of a uniform sphere of mass 100 kg and a radius of 10 cm. Find the work to be done against the gravitational force between them to take the particle far away from the sphere. (you may take G = 6.67×10⁻¹¹ Nm²/kg²)

A

3.33×10⁻¹⁰ J

B

13.34×10⁻¹⁰ J

C

6.67×10⁻¹⁰ J

D

6.67×10⁻⁹ J

Correct Answer

Option D

Detailed Explanation

To find the work done against the gravitational force to move the particle far away from the sphere, we use the formula for gravitational potential energy: U=−Gm1m2rU = -\frac{G m_1 m_2}{r}, where m1m_1 is the mass of the sphere (100 kg), m2m_2 is the mass of the particle (0.01 kg), rr is the distance from the center of the sphere (0.1 m), and GG is the gravitational constant 6.67×10−11 Nm2/kg26.67 \times 10^{-11} \, \text{Nm}^2/\text{kg}^2. Calculating this gives U=−6.67×10−9 JU = -6.67 \times 10^{-9} \, \text{J}, and the work done to move the particle to infinity is the positive of this potential energy, resulting in 6.67×10−9 J6.67 \times 10^{-9} \, \text{J} (option D).

Options A, B, and C are incorrect because they do not accurately reflect the calculated gravitational potential energy or the work required to overcome it, either underestimating or miscalculating the values involved.

Found an issue with this question?