AIIMS 2017 Physics Escape Velocity MCQ Question
The escape velocity from the earth is about 11 .The escape velocity from a planet having twice he radius and the same mean density as the earth is
22
22
22
22
Correct Answer
Detailed Explanation
The escape velocity is derived from the gravitational potential energy and kinetic energy relationship, specifically given by the formula , where is the gravitational constant, is the mass of the celestial body, and is its radius. Option C, , is incorrect because it omits the factor of 2, which is essential for calculating the velocity needed to escape a gravitational field. Options A and D also misrepresent the relationship by introducing incorrect constants or factors that do not align with the fundamental principles of gravitational physics.
Found an issue with this question?
Related Questions
More from Gravitation
More from 2017
Which of the following statements are correct? (A) Centre of mass of a body always coincides with the centre of gravity of the body. (B) Centre of m...
With reference to factors affecting the rate of photosynthesis, which of the following statements is NOT correct?
Which of the following options gives the CORRECT sequence of events during mitosis?