AIIMS 2019 Physics Acceleration due to Gravity MCQ Question

The difference between the acceleration of free fall (g') and the acceleration due to gravity (g) near the Earth's surface can be calculated using the formula $g' = g \left(1 - \frac{2h}{R}\right)$, where $h$ is the height above the Earth's surface and $R$ is the Earth's radius. Given that the radius of the Earth is 6347 km, the difference is approximately 0.3400 m/s², making option A correct. Other options (B, C, D) represent values that do not align with the calculated difference, as they are either too small or not relevant to the context of gravitational acceleration near the Earth's surface.