AIIMS2017Physics-Electrostatics

AIIMS 2017 Physics Capacitors MCQ Question

Type: MCQ-numerical-Medium-Class 12

A parallel plate capacitor has an electric field of 105 Vm110^5\text{ Vm}^{-1} between the plates. If the charge on the capacitor plates is 1 μC1\ \mu\text{C}, the force on each capacitor plate is

A

0.5 N

B

0.05 N

C

0.005 N

D

None of these

Correct Answer

Option A

Detailed Explanation

The force of attraction between two charged plates in a parallel plate capacitor can be expressed as F=12QEF = \frac{1}{2} QE, where QQ is the charge on the plates and EE is the electric field strength. This formula arises from the energy stored in the electric field, which is related to the force acting on the charge. Options B and C involve substituting values into the equation but do not provide a general understanding of the relationship, while option D incorrectly calculates the force without proper context or derivation from the original formula. Understanding this relationship is crucial for analyzing electric fields and forces in electrostatics.

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