AIIMS 2019 Physics Moving Charges and Magnetism MCQ Question

The ratio of the electric field (E) to the magnetic field (B) due to a moving point charge can be derived from the relationship $E = k \frac{q}{r^2}$ and $B = \frac{\mu_0}{4\pi} \frac{qv}{r^2}$, where $k$ is Coulomb's constant, $q$ is the charge, $v$ is the velocity, and $r$ is the distance from the charge. This leads to the ratio $\frac{E}{B} = \frac{c}{\mu_0}$, where $c$ is the speed of light, resulting in a value of approximately $2 \times 10^{11}$ for $v = 4.5 \times 10^5 \, \text{m/s}$. Other options are incorrect as they do not align with the derived ratio based on the fundamental principles of electromagnetism.