AIIMS 2018 Physics Magnetic Flux MCQ Question

In the given expression, $LI = N \cdot \left( \frac{\mu_0 I}{2a} \right) \times \pi a^2 \cdot N$, substituting $N = \frac{l}{2\pi a}$ leads to the relationship $L \propto a^{-1}$. This indicates that the inductance $L$ is inversely proportional to the radius $a$, which is a key concept in electromagnetism related to the geometry of the conductor. Other options are not applicable as they do not provide relevant information or calculations related to the inductance or electric flux in this context.