AIIMS2019Physics-Electromagnetism

AIIMS 2019 Physics Magnetic Field in Toroids MCQ Question

Type: MCQ-numerical-Hard-Class 12

In toroid magnetic field on axis will be the radius = 0.5 cm, current = 1.5A, turns = 250, permeability = 700.

A

7.5 Tesla

B

10.5 Tesla

C

4.5 Tesla

D

15.5 Tesla

Correct Answer

Option B

Detailed Explanation

The magnetic field BB at the center of a toroid can be calculated using the formula B=μNI2πrB = \frac{{\mu N I}}{{2 \pi r}}, where μ\mu is the permeability, NN is the number of turns, II is the current, and rr is the radius. Substituting the given values, B=700×250×1.52π×0.00510.5TB = \frac{{700 \times 250 \times 1.5}}{{2 \pi \times 0.005}} \approx 10.5 \, \text{T}, confirming option B as correct. Other options are incorrect as they do not match this calculated value, indicating either miscalculations or incorrect application of the formula.

Found an issue with this question?