AIIMS2018Physics-Electromagnetism

AIIMS 2018 Physics Inductance MCQ Question

Type: MCQ-conceptual-Medium-Class 12

If in a solenoid, a rod of relative permeability μr\mu_r is kept, then find the self-inductance of the solenoid (where N=N = number of turns, l=l = length of solenoid and A=A = area of solenoid).

A

μ0μrN2Al\frac{\mu_0\mu_rN^2A}{l}

B

μ0μrN2A2l\frac{\mu_0\mu_rN^2A}{2l}

C

μ0μrNA2l\frac{\mu_0\mu_rNA^2}{l}

D

μ0μrNA22l\frac{\mu_0\mu_rNA^2}{2l}

Correct Answer

Option A

Detailed Explanation

The expression for self-inductance LL is derived from the formula L=μ0μrN2AL = \mu_0 \mu_r \frac{N^2 A}{\ell}, where μ0\mu_0 is the permeability of free space, μr\mu_r is the relative permeability, NN is the number of turns, AA is the cross-sectional area, and \ell is the length of the coil. This formula indicates that self-inductance is directly proportional to the square of the number of turns and the area, and inversely proportional to the length of the coil. Since the other options are marked as N/A, they do not provide relevant or correct information regarding the self-inductance expression.

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