AIIMS2007Physics-Electromagnetism

AIIMS 2007 Physics Charge to Mass Ratio MCQ Question

Type: MCQ-conceptual-Medium-Class 12

In the following diagram, which particle has highest e/m value?

Question diagram
A

A

B

B

C

C

D

D

Correct Answer

Option D

Detailed Explanation

To determine which particle has the highest charge-to-mass ratio (denoted as em\frac{e}{m}), we will analyze the properties of the particles in question (A, B, C, and D) based on their charge ee and mass mm. The charge-to-mass ratio is defined as:

em\frac{e}{m}

where:

  • ee is the charge of the particle,
  • mm is the mass of the particle.

Explanation for Correct Answer (Option D)

  1. Charge-to-Mass Ratio: The particle denoted as D is found to have the highest em\frac{e}{m} value. This means that either it has a significantly higher charge ee compared to its mass mm, or it has a much lower mass while maintaining a comparable charge to the other particles.

  2. Concept of Charge and Mass: Generally, lighter particles (such as electrons) tend to have a higher charge-to-mass ratio compared to heavier particles (like protons or neutrons). If particle D is depicted as having a small mass and a relatively larger charge compared to the other particles, this would contribute to a higher em\frac{e}{m}.

Clarification of Other Options

  • Option A, B, and C: Without specific values or descriptions from the diagram, we can infer that these particles either have:
    • A larger mass, which would reduce their em\frac{e}{m} ratio if their charge remains constant.
    • A smaller charge, which would also lead to a lower em\frac{e}{m}.
    • A combination of both larger mass and smaller charge.

Relevant Formulas and Concepts

To calculate em\frac{e}{m} for any particle, one would typically use:

em=Charge of particleMass of particle\frac{e}{m} = \frac{\text{Charge of particle}}{\text{Mass of particle}}

If we had numerical values for the charges and masses of particles A, B, C, and D, we could explicitly calculate the ratios. For example:

  • If particle A has eA=1Ce_A = 1 \, \text{C} and mA=2kgm_A = 2 \, \text{kg}:

    eAmA=12=0.5C/kg\frac{e_A}{m_A} = \frac{1}{2} = 0.5 \, \text{C/kg}
  • If particle D has eD=1Ce_D = 1 \, \text{C} and mD=0.1kgm_D = 0.1 \, \text{kg}:

    eDmD=10.1=10C/kg\frac{e_D}{m_D} = \frac{1}{0.1} = 10 \, \text{C/kg}

In this hypothetical example, it is clear that particle D has a much higher charge-to-mass ratio.

Conclusion

In conclusion, the particle that holds the highest charge-to-mass ratio em\frac{e}{m} is option D. This is likely due to its smaller mass and/or higher charge compared to the other particles. Understanding the implications of mass and charge in determining the charge-to-mass ratio is crucial in fields such as electromagnetism and particle physics.

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