AIIMS2019Physics-Electromagnetic Induction

AIIMS 2019 Physics Transformers MCQ Question

Type: MCQ-numerical-Medium-Class 12

For an ideal transformer power input is equal to power output.

P_{in} = P_{out}

E_p I_p = \frac{V_s2s^2}{R_s}

1000 ×\times 50 = \frac{2202220^2}{R_s}

R_s = 0.968 Ω\Omega

\approx 1 Ω\Omega

A

0.5 Ω

B

1 Ω

C

2 Ω

D

4 Ω

Correct Answer

Option C

Detailed Explanation

In the given problem, the relationship between input and output power in an ideal transformer is utilized to find the secondary resistance RsR_s. By rearranging the equation Pin=PoutP_{in} = P_{out} and substituting the known values, we find Rs0.968ΩR_s \approx 0.968 \, \Omega, which rounds to approximately 1Ω1 \, \Omega, making option (B) the closest correct answer. Options (A), (C), and (D) are incorrect as they do not match the calculated resistance; specifically, 0.5Ω0.5 \, \Omega is too low, 2Ω2 \, \Omega and 4Ω4 \, \Omega are too high, demonstrating the importance of accurate calculations in electrical engineering principles.

Found an issue with this question?