AIIMS 2019 Physics Transformers MCQ Question
A transformer consists of 500 turn in primary coil and 10 turns in secondary coil with the load of 10 Ω. Find out current in the primary coil when the voltage across secondary coil is 50 V.
5 A
1 A
10 A
2 A
Correct Answer
Detailed Explanation
In this scenario, we can use the principle of conservation of energy in transformers, which states that the power in the primary coil (Pₚ) equals the power in the secondary coil (Pₛ). Given that P = V × I, we can express this as Vₚ × iₚ = Vₛ × iₛ. Substituting the known values, we find that iₚ = (Vₛ × iₛ) / Vₚ = (50 V × 5 A) / 2500 V = 1 A. However, since the question does not provide a corresponding option for this value, option B (N/A) is correct as it indicates that no suitable answer is available. The other options are incorrect as they do not provide valid current values based on the calculations.
Found an issue with this question?