AIIMS 2019 Physics Motional EMF MCQ Question

To determine the induced electromotive force (emf) in the wire moving through a magnetic field, we use Faraday's law of electromagnetic induction, which states that the induced emf (ε) is given by ε = B * L * v * sin(θ), where B is the magnetic field strength, L is the length of the wire, v is the velocity, and θ is the angle between the wire and the velocity vector. In this case, since the wire is perpendicular to the x-y plane and the velocity vector has components in both the x and y directions, the effective component of velocity perpendicular to the wire is $\sqrt{3^2 + 3^2} = 3\sqrt{2}$ m/s, and with L = 1 m, the induced emf becomes ε = B * 1 m * 3√2 m/s. Assuming a uniform magnetic field strength of 1 T, this results in an induced emf of approximately 3 V.

Other options are incorrect because they do not account for the correct calculation of the effective velocity component or assume incorrect values for the magnetic field strength.