AIIMS 2019 Physics LCR Circuits MCQ Question

At resonance in an LCR circuit, the impedance is minimized, and the current is maximized. The energy stored in the inductor (U) can be calculated using the formula $U = \frac{1}{2} L I^2$, where $L = 1 \, \text{H}$ and $I$ is the maximum current. The maximum current $I$ can be found using Ohm's law, $I = \frac{V}{R} = \frac{10 \, \text{V}}{10 \, \Omega} = 1 \, \text{A}$. Substituting these values gives $U = \frac{1}{2} \times 1 \, \text{H} \times (1 \, \text{A})^2 = 0.5 \, \text{J}$. Other options are incorrect as they do not align with the calculated energy stored in the inductor at resonance.