AIIMS2018Physics-Current Electricity

AIIMS 2018 Physics Shunt Resistance MCQ Question

Type: MCQ-numerical-Medium-Class 12

The expression for the shunt resistance is given by, S = \frac{I_g G}{I - I_g} Substitute 0.5 μA for I_g, 5 Å for I and 50 Ω for G in the above equation.

A

5 × 10⁻⁶ Ω

Correct Answer

Option A

Detailed Explanation

To find the shunt resistance SS, we substitute the given values into the formula S=IgGIIgS = \frac{I_g G}{I - I_g}. Using Ig=0.5μA=0.5×106AI_g = 0.5 \, \mu A = 0.5 \times 10^{-6} \, A, I=5AI = 5 \, A, and G=50Ω1G = 50 \, \Omega^{-1}, we calculate S=(0.5×106)×5050.5×1065×106ΩS = \frac{(0.5 \times 10^{-6}) \times 50}{5 - 0.5 \times 10^{-6}} \approx 5 \times 10^{-6} \, \Omega. The other options are not applicable since they do not provide valid answers or calculations related to the question.

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