AIIMS2019Physics-Current Electricity

AIIMS 2019 Physics Ohm's Law MCQ Question

Type: MCQ-numerical-Medium-Class 12

For a wire Rl=12\frac{R}{l} = \frac{1}{2} and length of wire is l=5l = 5 cm. If potential difference 1 V is applied across it, current through wire will be: (R = Resistance)

A

40 Å

B

4 Å

C

25 Å

D

2.5 Å

Correct Answer

Option A

Detailed Explanation

To find the current through the wire, we first determine its resistance RR using the formula R=RllR = \frac{R}{l} \cdot l. Given Rl=12Ω/cm\frac{R}{l} = \frac{1}{2} \, \Omega/\text{cm} and l=5cml = 5 \, \text{cm}, the resistance is R=125=2.5ΩR = \frac{1}{2} \cdot 5 = 2.5 \, \Omega. Applying Ohm's Law V=IRV = IR, where V=1VV = 1 \, \text{V}, we find the current I=VR=12.5=0.4A=40mAI = \frac{V}{R} = \frac{1}{2.5} = 0.4 \, \text{A} = 40 \, \text{mA} (or 40 Å).

Options B (4 Å), C (25 Å), and D (2.5 Å) are incorrect as they do not align with the calculated current based on the given resistance and applied voltage.

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