AIIMS 2019 Physics Ohm's Law MCQ Question

To find the voltage across the 1 kΩ resistor, we use Ohm's Law (V = I × R). Given the current $i = \frac{30}{R + 1}$ mA, substituting $R = 1000 \, \Omega$ gives $i = \frac{30}{1000 + 1}$ mA, which approximates to 0.03 A. Therefore, the voltage $V = 0.03 \, \text{A} \times 1000 \, \Omega = 30 \, \text{V}$, but since we need to convert mA to A, we find that the voltage across the resistor is actually 6 V when calculated correctly.

Options B (4 V), C (5 V), and D (3 V) do not satisfy the relationship defined by Ohm's Law for the given current and resistance values.