AIIMS2019Physics-Atomic Structure

AIIMS 2019 Physics Energy Levels MCQ Question

Type: MCQ-numerical-Medium-Class 11

An electron collides elastically with H⁻like atom and excites it from ground state to n = 3. Find out the energy transfer to H⁻like atom

A

12.1 eV

B

10.2 eV

C

12.75 eV

D

10 eV

Correct Answer

Option A

Detailed Explanation

To determine the energy transfer to a H⁻-like atom when it is excited from the ground state (n = 1) to n = 3, we use the formula for the energy levels of a hydrogen-like atom: En=Z213.6eVn2E_n = -\frac{Z^2 \cdot 13.6 \, \text{eV}}{n^2}. For H⁻ (where Z = 1), the energy levels are E1=13.6eVE_1 = -13.6 \, \text{eV} and E3=13.69eVE_3 = -\frac{13.6}{9} \, \text{eV}, resulting in an energy difference of ΔE=E3E1=13.69+13.6=12.1eV\Delta E = E_3 - E_1 = -\frac{13.6}{9} + 13.6 = 12.1 \, \text{eV}.

Options B (10.2 eV), C (12.75 eV), and D (10 eV) are incorrect because they do not correspond to the calculated energy difference between the specified energy levels for a H⁻-like atom.

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