AIIMS2019Physics-Atomic Structure

AIIMS 2019 Physics Bohr's Model MCQ Question

Type: MCQ-numerical-Medium-Class 11

The radius of electron in excited state is given by, r = r₀ (n²/Z) For the radius to be equal to radius of hydrogen atoms, r = r₀. Therefore, r₀ = r₀ (n²/Z) n = √Z = √4 = 2 Thus, at first excited state of Be³⁺ radius of e⁻ will be same as H atoms and electron in ground state.

A

2

B

3

C

4

D

5

Correct Answer

Option A

Detailed Explanation

For the radius of an electron in the first excited state of Be³⁺ to equal that of a hydrogen atom, we set the equation r=r0(n2Z)r = r_0 \left( \frac{n^2}{Z} \right) equal to r0r_0. This leads to n2=Zn^2 = Z, where ZZ for Be³⁺ is 4, giving n=4=2n = \sqrt{4} = 2. Options B (3), C (4), and D (5) are incorrect because they do not satisfy the condition n2=Zn^2 = Z for the first excited state of Be³⁺, which specifically requires n=2n = 2.

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