AIIMS2019Physics-Atomic Structure

AIIMS 2019 Physics Bohr's Model MCQ Question

Type: MCQ-numerical-Medium-Class 12

If energy of electron in ground state is −13.6 then find out speed of electron in fourth orbit of H⁻atom

A

5.45×10⁶ m/s

B

5.45×10⁵ m/s

C

5.45×10⁵ m/s

D

4.45×10⁵ m/s

Correct Answer

Option B

Detailed Explanation

To find the speed of the electron in the fourth orbit of a hydrogen atom (H⁻), we can use the formula for the speed of an electron in a Bohr orbit: vn=Ze22ε0h1nv_n = \frac{Z e^2}{2 \varepsilon_0 h} \cdot \frac{1}{n}, where ZZ is the atomic number (1 for H), ee is the elementary charge, ε0\varepsilon_0 is the permittivity of free space, hh is Planck's constant, and nn is the principal quantum number (4 for the fourth orbit). Substituting the values yields a speed of approximately 5.45×105m/s5.45 \times 10^5 \, \text{m/s}, confirming option B.

Options A and C are incorrect as they provide the same incorrect speed of 5.45×106m/s5.45 \times 10^6 \, \text{m/s}, which is too high for the fourth orbit, while option D, 4.45×105m/s4.45 \times 10^5 \, \text{m/s}, underestimates the speed based on the same formula. Understanding the relationship between energy levels and electron speeds in atomic orbits is crucial for mastering atomic physics concepts.

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