AIIMS2018Physics-Atomic Structure

AIIMS 2018 Physics Bohr's Model MCQ Question

Type: MCQ-conceptual-Medium-Class 11

Find out the velocity of electron in second orbit of helium.

A

2.1×10⁶ m/s

B

4.2×10⁶ m/s

C

2.1×10⁴ m/s

D

4.2×10⁴ m/s

Correct Answer

Option A

Detailed Explanation

In the second orbit of helium (He), which has two electrons, the velocity of an electron can be calculated using the Bohr model formula for hydrogen-like atoms: vn=Ze24πϵ01nv_n = Z \cdot \frac{e^2}{4 \pi \epsilon_0 \hbar} \cdot \frac{1}{n}, where ZZ is the atomic number (2 for helium), ee is the elementary charge, ϵ0\epsilon_0 is the permittivity of free space, \hbar is the reduced Planck's constant, and nn is the principal quantum number (2 for the second orbit). Substituting the values yields a velocity of approximately 2.1×106m/s2.1 \times 10^6 \, \text{m/s}, confirming option (A) as correct.

Options (B), (C), and (D) are incorrect as they either overestimate or underestimate the electron's velocity based on the fundamental principles of quantum mechanics and the specific parameters for helium's electron configuration.

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