The wavelengths of K$ \alpha $ X⁻rays for lead isotopes $ ^{208}Pb, ^{206}Pb $ and $ ^{204}Pb $ are $ \lambda_2, \lambda_4 $ and $ \lambda_3 $ respectively.

Question

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$ \lambda_2 = \sqrt{\lambda_3} $

Answer

$ \lambda_2 = \lambda_1 + \lambda_3 $

Answer

$ \lambda_2 = \lambda_1\lambda_3 $

Answer

$ \lambda_2 = \frac{\lambda_1}{\lambda_3} $

AIIMS 2009 Physics X-ray Spectra MCQ Question

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