AIIMS2019Chemistry-Acids and Bases

AIIMS 2019 Chemistry Salt hydrolysis MCQ Question

Type: MCQ-numerical-Medium-Class 12

The pH of the salt is, pH = 1/2 (pKₐ + pK_b + pK_w) = 1/2 (14 + 4 - 5) = 6.5

Correct Answer

Option A

Detailed Explanation

The calculation of pH using the formula pH=12(pKa+pKb+pKw)\text{pH} = \frac{1}{2} (\text{p}K_a + \text{p}K_b + \text{p}K_w) is valid for a salt formed from a weak acid and a weak base, where pKw\text{p}K_w is the ion product of water (14 at 25°C). In this case, substituting the values pKa=4\text{p}K_a = 4, pKb=5\text{p}K_b = 5, and pKw=14\text{p}K_w = 14 yields a pH of 6.5, indicating a neutral solution. Since all other options are marked as N/A, they do not provide relevant alternatives or correct answers.

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