AIIMS2019Chemistry-Carbohydrates

AIIMS 2019 Chemistry Structure of Glucose Assertion Reason Question

Type: Assertion Reason-conceptual-Medium-Class 12

In glucose, there is absence of free aldehyde group and it forms cyclic hemiacetal form as shown below.

Question diagram

Correct Answer

Option A

Detailed Explanation

Glucose, a monosaccharide, predominantly exists in a cyclic form due to the reaction between its aldehyde group and a hydroxyl group, forming a hemiacetal. In its cyclic structure, the aldehyde group is converted into a hemiacetal, resulting in the formation of a six-membered ring (pyranose form) where the free aldehyde group is no longer present. Other options are not applicable as they do not provide relevant information or alternative structures related to glucose's cyclic form. Understanding this transformation is crucial for grasping carbohydrate chemistry and the behavior of sugars in biological systems.

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