AIIMS2019Chemistry-Carboxylic Acids and Derivatives

AIIMS 2019 Chemistry Ester Hydrolysis MCQ Question

Type: MCQ-conceptual-Medium-Class 12

HCOH+CH3CH=OConc. NaOH\text{H}-\overset{\substack{\text{O} \\ ||}}{\text{C}}-\text{H} + \text{CH}_3-\text{CH}=\text{O} \xrightarrow{\text{Conc. NaOH}} Find out the products of reaction

A

CH3CO2Na & CH3OH\text{CH}_3\text{CO}_2\text{Na} \text{ \& } \text{CH}_3\text{OH}

B

CH3CH2OH+CH3OH\text{CH}_3\text{CH}_2\text{OH} + \text{CH}_3\text{OH}

C

CH3CH2OH & HCO2Na\text{CH}_3\text{CH}_2\text{OH} \text{ \& } \text{HCO}_2\text{Na}

D

CH3CO2Na & HCO2Na\text{CH}_3\text{CO}_2\text{Na} \text{ \& } \text{HCO}_2\text{Na}

Correct Answer

Option A

Detailed Explanation

The reaction between acetyl chloride (CH₃COCl) and ethanol (CH₃CH₂OH) in the presence of concentrated sodium hydroxide (NaOH) leads to the formation of sodium acetate (CH₃CO₂Na) and methanol (CH₃OH) through a nucleophilic substitution mechanism. The NaOH acts as a base, facilitating the deprotonation of ethanol and allowing it to attack the carbonyl carbon of acetyl chloride, resulting in the formation of the carboxylate salt and methanol.

Option B is incorrect because it suggests that the reactants remain unchanged, while option C incorrectly implies the formation of formate salts, which do not arise from the given reactants. Option D also misrepresents the products by including formate salts instead of acetate.

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