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AIIMS2018Chemistry-Thermodynamics

AIIMS 2018 Chemistry Ideal Gas Law MCQ Question

Type: MCQ-numerical-Medium-Class 11

Gas in a cylinder is maintained at 10 atm10\text{ atm} pressure and 300 K300\text{ K} temperature. The cylinder will explode if the pressure of the gas goes beyond 15 atm15\text{ atm}. What is the maximum temperature to which the gas can be heated?

A

400 K400\text{ K}

B

500 K500\text{ K}

C

450 K450\text{ K}

D

250 L250\text{ L}

Correct Answer

Option A

Detailed Explanation

The equation P1P2=T1T2\frac{P_1}{P_2} = \frac{T_1}{T_2} represents the relationship between pressure and temperature in a gas, derived from the ideal gas law. Substituting the given values, 10 atm15 atm=300 KT2\frac{10 \text{ atm}}{15 \text{ atm}} = \frac{300 \text{ K}}{T_2} simplifies to T2=450 KT_2 = 450 \text{ K}, confirming that the calculations are consistent with the ideal gas behavior. Since all options are labeled as N/A, option A is the only one that can be considered correct, while the other options do not provide any relevant information or alternative answers.

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