AIIMS 2019 Chemistry Hess's Law MCQ Question

To derive the formation reaction of C₂H₅OH(l), the enthalpy changes from reactions (I), (II), and (III) are manipulated according to Hess's law. By multiplying reaction (I) by 2 and reaction (II) by 3, and then adding these to reaction (III), the total enthalpy change is calculated as ΔH = [–393 kJ mol⁻¹ × 2] + [–287.3 kJ mol⁻¹ × 3] + 1366.8 kJ mol⁻¹, resulting in ΔH = –281.1 kJ mol⁻¹ for the formation of C₂H₅OH(l). Other options are not applicable as they do not provide relevant enthalpy values or calculations related to the formation reaction.