AIIMS 2014 Chemistry de-Broglie wavelength MCQ Question

The de-Broglie wavelength ($\lambda$) of a particle is given by the equation $\lambda = \frac{h}{mv}$, where $h$ is Planck's constant, $m$ is the mass, and $v$ is the velocity of the particle. Given that the de-Broglie wavelength is 100 times its velocity ($\lambda = 100v$), we can set up the equation $100v = \frac{h}{mv}$. Rearranging and solving for $\lambda$ in terms of $m$ and $h$ leads to $\lambda = \frac{1}{10} \sqrt{\frac{h}{m}}$, confirming that the correct answer is A.