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AIIMS 2017 Chemistry Limiting Reagents MCQ Question

Type: MCQ-numerical-Medium-Class 11

If 0.5 moles0.5\text{ moles} of BaCl2\text{BaCl}_2 is mixed with 0.2 moles0.2\text{ moles} of Na3PO4\text{Na}_3\text{PO}_4, the maximum number of moles of Ba3(PO4)2\text{Ba}_3(\text{PO}_4)_2 that can be formed is:

A

0.7

B

0.5

C

0.03

D

0.10

Correct Answer

Option A

Detailed Explanation

In the reaction between BaCl₂ and Na₃PO₄, 2 moles of Na₃PO₄ produce 1 mole of Ba₃(PO₄)₂. Given that only 0.2 moles of Na₃PO₄ are available, the maximum amount of Ba₃(PO₄)₂ that can be formed is calculated as 0.2 moles Na₃PO₄2=0.1 moles Ba₃(PO₄)₂\frac{0.2 \text{ moles Na₃PO₄}}{2} = 0.1 \text{ moles Ba₃(PO₄)₂}. Other options are incorrect because they exceed the stoichiometric yield based on the limiting reagent, Na₃PO₄, which restricts the formation of Ba₃(PO₄)₂ to 0.1 moles.

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