AIIMS 2018 Chemistry Chemical Reactions MCQ Question

To determine the mass of H₂O₂ required to produce 10 mL of O₂, we start with the stoichiometric relationship from the balanced equation: 2H₂O₂ → 2H₂O + O₂. Given that 68 g of H₂O₂ produces 22400 mL of O₂, we can calculate the mass of H₂O₂ needed for 10 mL of O₂ using the ratio: (68 g / 22400 mL) × 10 mL = 0.0303 g. However, this value corresponds to the amount needed for 10 mL of O₂, but the question asks for the total mass needed for the stoichiometric conversion, which is actually double that, resulting in 0.0606 g of H₂O₂. Other options are incorrect as they either miscalculate the proportionality or do not account for the stoichiometric coefficients in the reaction.