AIIMS 2019 Chemistry Calculations involving moles MCQ Question
By going through options, calculate the weight of the given substances.
Weight of H₂ = mole × molecular weight = 0.2 × 2 = 0.4 g
6.023 × 10²³ = 1 mol, 6.023 × 10²² = 0.1 mol. The weight of Nitrogen, N₂ = 0.1 × 28 = 2.8 g
Weight of silver is 0.1 g
Weight of oxygen = 32 × 0.1 = 3.2 g
Correct Answer
Detailed Explanation
Option C states that the weight of silver is 0.1 g, which is a straightforward assertion without any calculations, making it a plausible answer. In contrast, option A incorrectly calculates the weight of H₂ as 0.4 g, which is correct; however, it does not provide a comparison to other options. Option B miscalculates the weight of N₂ by stating it as 2.8 g for 0.1 mol, which is incorrect since 0.1 mol of N₂ (molecular weight 28 g/mol) should weigh 2.8 g, but the context of the question implies a need for clarity in the comparison. Option D incorrectly calculates the weight of oxygen as 3.2 g for 0.1 mol, which is also misleading since 0.1 mol of O₂ (molecular weight 32 g/mol) should weigh 3.2 g, but again, the context suggests a need for clarity in the comparison. Understanding molecular weights and their application in calculating mass is essential for solving such problems accurately.
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