AIIMS 2019 Chemistry Vapour Pressure MCQ Question
The mole fraction of solute is equal to the relative lowering of vapour pressure, x₂ = (P₀ - Pₛ) / P₀. Substitute the given values in the above equation.
(0.5/65) =¹⁴³⁻ Pₛ / 143
(158/154)
After solving, Pₛ = 141.93 mm Hg
Correct Answer
Detailed Explanation
Option A is correct because it accurately represents the relationship between the mole fraction of the solute (x₂) and the relative lowering of vapor pressure, given by the equation . In this equation, is the vapor pressure of the pure solvent (e.g., H₂O), and is the vapor pressure of the solution. The other options either provide incorrect numerical values or fail to correctly apply the formula, making them invalid in the context of this problem. Understanding this relationship is crucial for solving problems related to colligative properties in solutions.
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