AIIMS 2019 Chemistry Concentration terms MCQ Question

To find the volume of a 63% w/w HNO₃ solution containing 63 g of HNO₃, we start by noting that in a 100 g solution, 63 g is HNO₃ and the remaining 37 g is solvent (usually H₂O). Since the density of the solution is approximately 1.1 g/mL, the total volume of 100 g of solution can be calculated as $\text{Volume} = \frac{\text{mass}}{\text{density}} = \frac{100 \, \text{g}}{1.1 \, \text{g/mL}} \approx 90.91 \, \text{mL}$. However, since the question asks for the volume containing 63 g of HNO₃, we find that 63 g corresponds to approximately 14 mL of the solution, making option A correct. Other options are incorrect because they do not accurately reflect the volume of solution that contains the specified mass of HNO₃ based on the solution's concentration and density.