AIIMS2018Chemistry-Solutions

AIIMS 2018 Chemistry Colligative Properties MCQ Question

Type: MCQ-conceptual-Medium-Class 12

Freezing point of 0.4 m0.4\text{ m} solution of a weak monoprotic acid is 0.1C-0.1^\circ\text{C}. What is its van 't Hoff factor ii ?

A

1.5

B

1.6

C

1.34

D

1.1

Correct Answer

Option C

Detailed Explanation

The Van 't Hoff factor, ii, represents the degree of dissociation of a solute in a solvent, influencing colligative properties like freezing point depression. In the case of ionic compounds, ii can be expressed as i=1+α(n1)i = 1 + \alpha(n - 1), where α\alpha is the degree of dissociation and nn is the number of particles the solute dissociates into. Option C correctly reflects this relationship, indicating that as α\alpha increases, ii increases proportionally based on the number of dissociated particles.

Options A and B incorrectly suggest that the relationship is additive or subtractive in a way that does not accurately represent the dissociation process, while option D fails to account for the contribution of the original solute particle, leading to an incomplete understanding of the factor's calculation.

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