AIIMS 2017 Chemistry Noble Gas Compounds MCQ Question

When xenon (Xe) and fluorine (F₂) are present in a 1:5 ratio, the stoichiometry favors the formation of xenon tetrafluoride (XeF₄) due to the availability of excess fluorine, which allows for the formation of a stable compound with four fluorine atoms bonded to one xenon atom. In contrast, when Xe and F₂ are present in a 1:1 ratio, xenon difluoride (XeF₂) is formed, and in a 1:20 ratio, xenon hexafluoride (XeF₆) is produced, indicating that the number of fluorine atoms directly influences the type of xenon fluoride formed. Therefore, option B (XeF₄) is correct, while options A (XeF₂) and C (XeF₆) do not match the specified ratio conditions for their formation.