AIIMS2018Chemistry-Equilibrium

AIIMS 2018 Chemistry Solubility Product MCQ Question

Type: MCQ-numerical-Medium-Class 11

Solubility of a sparingly soluble salt XB2\text{XB}_2 in water is xx. What will be its solubility in a solution of yB\text{yB} having concentration of 0.001M0.001\text{M} ?

A

x2×106x^2 \times 10^{-6}

B

4x3×1064x^3 \times 10^6

C

4x3×1064x^3 \times 10^{-6}

D

4x3×1034x^3 \times 10^3

Correct Answer

Option B

Detailed Explanation

In the given reaction, the solubility product (Kₛₚ) is expressed as Kₛₚ = [X²⁺][B⁻]². Given that Kₛₚ = 4 × 3 × S × (0.001)², we can deduce that S represents the solubility of the salt in moles per liter. Since the equation simplifies to Kₛₚ = 12S × 10⁻⁶, it indicates that the solubility product is dependent on the concentration of the ions in solution, confirming that option B is the correct representation of this relationship. The other options are not relevant as they do not provide any valid Kₛₚ values or interpretations related to the solubility product.

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