AIIMS2017Chemistry-Chemical Equilibrium

AIIMS 2017 Chemistry Hydrolysis MCQ Question

Type: MCQ-numerical-Medium-Class 11

Calculate the degree of hydrolysis and pH\text{pH} of 0.02 M0.02\text{ M} ammonium cyanide (NH4CN\text{NH}_4\text{CN}) at 298 K298\text{ K}

(Ka of HCN=4.99×109K_a \text{ of HCN} = 4.99 \times 10^{-9}, Kb of NH4OH=1.77×105K_b \text{ of NH}_4\text{OH} = 1.77 \times 10^{-5})

A

8.2

B

3.2

C

9.3

D

3.9

Correct Answer

Option B

Detailed Explanation

Option B correctly calculates the value of hh using the hydrolysis constant KhK_h. The formula h=Kh1+Khh = \frac{\sqrt{K_h}}{1 + \sqrt{K_h}} is applied here, where KhK_h is derived from the provided values, resulting in h0.51h \approx 0.51.

Option A miscalculates KhK_h by not correctly applying the values, leading to an incorrect result. Option C uses an inaccurate pKapK_a and misapplies logarithmic properties, resulting in an incorrect pH calculation. Understanding hydrolysis constants and their relationship to equilibrium concentrations is crucial for accurately determining hh and pH in aqueous solutions.

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